SEPTEMBER THREAD - updated regularly

SEPTEMBER THREAD - updated regularly

1)col a:(2^8)*(15^5)+(2^8)*(15^5)
col b:(5^10)*(8^2)
Ans- B

2) Given that x*=(x-1)/x condition is x<0 x="x*..." x=" 9000/600" 99 =" 3^99" 33 =" 9^33" y="-5" y="5" 2y="5" 3y="-15" cube="X" cube="Xroot2" surface="Xroot2*X=" 2="main"> 0 & X>Y
Col A -------------------XZ
Col B-------------------YZ.
Sol: Case I: X=3, Y=2, Z=1 then col A is Greater.
Case II: X=5, Y= -2, Z= -3 then Col B is Greater
Therefore the answer is D

15). the mean of the three numbers 2X, 7X, X^2 (X square) is 12 what is the range of the given data (X<0). 3 =" 12" 2="36" 36="0" x=" -12" range =" Highest" commodity =" 144-" 3y="4" 4 =" 1" 3 =" 1" circle =" Pi" circle =" Pi" probability ="number" chance =" (X^2)">--------------------Number of people use only pagers
Col B ------------------------------------------------------- X – 12
Sol: Draw a Venn diagram Total number of people who watch television = 84.
No of people who watch TV and use pager = 84-X
Number of people who use only pager = 72- (84 – X) = 72- 84 + X = X- 12 Therefore C is the answer.

20). Find the Y – intercept of the equation 3X-2Y=5
Sol: X/ (5/3) + Y/ (-5/2) = 1,
Therefore the Y intercept is: -5/2

21). The amount of Rs.600/- is given at a rate of X% per annum , If he receives additional Rs.90/- after an year then what is the rate of interest ( i.e.- X )
Sol: For 600 rupees ------------------------90 rupees interest For 100 rupees-------------------------X X= 9000/600 = 15 rupees for 100 , which means 15%